Question

if cot x=-5/12,x lies in second quadrant,find the value of tan2x
Plz write the answer fast

Answer 1

ANSWER:

$\cot(x) = \frac{ - 5}{12} \\ = > \frac{1}{ \tan(x) } = - \frac{5}{12} \\ = > \tan(x) = - \frac{12}{5} \\ \\ \\ now \: \tan(2x) = \frac{ 2\tan(x) }{1 - {tan}^{2} (x)} \\ = > \tan(2x) = \frac{2 \times - \frac{12}{5} }{1 - \frac{144}{25} } \\ = > \tan(2x) = \frac{ - \frac{24}{5} }{ - \frac{ 119}{25} } \\ = > \tan(2x) = \frac{120}{119}$

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