Question

If cot0 = 1; find the value of 5 tan² 0 + 2 sin² 0 - 3 0 = thita​

Answer 1

Step-by-step explanation:

cotΘ=1

cotΘ=cot45

Θ=45∘

5tan2Θ+2sin2Θ−3

= 5tan245+2sin245−3

= 5(1)2+2(21)2−3

= 5+1−3

= 3

Answer 2

cotΘ=1

cotΘ=cot45

Θ=45

∘

5tan

2

Θ+2sin

2

Θ−3

= 5tan

2

45+2sin

2

45−3

= 5(1)

2

+2(

2

1

)

2

−3

= 5+1−3

= 3

hope it helps...✌️☺️