Question

Three resistors 10 Ω, 20 Ω and 50 Ω are connected in parallel, what is the total
resistor of the combination? If the combination is connected to a battery of emf 100 V and internal resistance
of 2 Ω then obtain the current through each resistor.

Answer 1

Answer:

Explanation:

For parallel conection formula is 1/Rp= 1/r1+1/r2=1/r3

total resisitor will be= 1/10+1/20+1/50

lcm= 100

so, 10+5+2= 17/100 ohm

the total resistor will be=5.882

not sure about 2nd part