Question

If cot0 = 40/9
find the values of coseco0 and sine0​

Answer 1

Answer:

cot=40/9= P/B

By Pythagoras theorem

$h { }^{2} = p {}^{2} + b {}^{2}$

$h {}^{2} =( 40 {)}^{2} + (9) {}^{2}$

$h {}^{2} = 1600 + 81 \\ h {}^{2} = 1681 \\ h = \sqrt{ 1681 } \\ h = 41$

cosec0= B/H= 9/41

sin 0= P/H= 40/41

Answer 2

Answer:

I hope this answer is help full