If cot2 theta =3; then cosec theta
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Cot²ø = 3
=> Cos²ø = 3
Sin²ø 1
=> Cosec²ø = 3
Sec²ø 1
=> Cosec ø = root 3
and sec ø = 1
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Answered by
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Step-by-step explanation:
cot 2 theta = 3
cot theta= 3/2
cot theta= B/P =3/2
Hence, B=3 AND P=2
Using Pythagoras theorem,
H^2 = B^2 + P^2
H^2 = 3^2+ 2^2
H^2= 9+4
H = ✓13
so, cosec theta = H/P
= ✓13/2
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