if cot⁴∅-cot²∅=1 then show that sec⁴∅-sec²∅= 1
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Answer: LHS
= 2sec² θ – sec⁴ θ – 2 cosec²θ + cosec⁴ θ
= sec² θ (2 – sec² θ) – cosec²θ (2 - cosec² θ)
Now we will replace sec² θ by 1 + tan² θ and cosec² θ by 1+ cot² θ
= (1+tan² θ) (2 –1-tan² θ) – (1+cot² θ)(2 - 1-cot² θ)
=(1+tan² θ)(1-tan² θ)-(1+cot² θ)(1-cot² θ)
=(1-tan⁴ θ) - (1-cot⁴ θ)
=cot⁴ θ -tan⁴ θ
Step-by-step explanation: PLEASE MARK ME THE BRAINLEIST
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