If cotA=4/3, find the value of 1/sinA+1/cosA
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Answer:
cotA4/3
cot=b/p
A B=3
BC=4
AC=?
by using pythagora's theorem
H²=B²+P²
H²=4²+3²
H²=16+9
H²=25
H=root over 25
H=+-5
we can't take hypotenuse as negative
now,
1/SINA+1/COSA
1/P/H+1/B/H
1/3/4+1/4/5
1×4/3+1×5/4
4/3+5/4
16+15/12
26/12
13/6
2¹/6
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