Question

If cotv=2x/√9+4x^2, then evaluate sinv+cosv

Answer 1

$\underline\bold{\huge{ANSWER \: :}}$



$\bold{INTRODUCTION\: TO\:TRIGONOMETRY}$

✔ Trigonometry is the study of relationships between the sides and the angles of a triangle.

✔ The general trigonometric ratios are sin theta, cos theta, tan theta, sec theta, cosec theta and cot theta.

______________________________

We all know a triangle has three parts : base, height and hypotenuse.

✔ Sin theta = height/hypotenuse.

✔ Cos theta = base/hypotenuse.

✔ tan theta = height /base.

✔ cot theta = base/height.

✔ sec theta = hypotenuse/base.

✔ cosec theta = hypotenuse/height.


______________________________



GIVEN, Cot v = (2x)/{√(9+4x²)}

We also know, Cot v = Cos v/Sin v.

So, Cos v = 2x.

Sin v = √(9+4x²)

$\bold{THUS\:\:THE\:\:ANSWER\:\:IS :}$

Sin v + Cos v

= √(9+4x²) + 2x

= 2x + √(9+4x²) [ANSWER]