if cp and cv denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then 1) cp-cv = r/28 2) cp-cv = r/14 3) cp-cv = r 4) cp-cv = 28r
Answers
Answered by
22
As nitrogen is a diatomic gas.
In case of diatomic gases:-
Specific heat of one gram mole of gas at constant volume (Cv) is given by :- Cv = 52R ........(1)
and Specific heat of one gram mole of gas at constant pressure (Cp) is given by :- Cp=72R.....(2)
Subtracting eq 1 from eq 2, we get :-
Cp - Cv = R where R is a gas constant
In case of diatomic gases:-
Specific heat of one gram mole of gas at constant volume (Cv) is given by :- Cv = 52R ........(1)
and Specific heat of one gram mole of gas at constant pressure (Cp) is given by :- Cp=72R.....(2)
Subtracting eq 1 from eq 2, we get :-
Cp - Cv = R where R is a gas constant
Answered by
26
In case of diatomic gases like nitrogen
specific heat of 1gm mole of gas at constant volume= Cv= 5/2 R
specific heat of 1gm mole of gas at constant pressure = Cp= 7/2 R
subtracting both equations we get
Cp - Cv = R
specific heat of 1gm mole of gas at constant volume= Cv= 5/2 R
specific heat of 1gm mole of gas at constant pressure = Cp= 7/2 R
subtracting both equations we get
Cp - Cv = R
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