if current =5 micro ampere and resistance=600 Johnston's potential difference
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v=IR
Answered by
1
micro ampere mean 5×10^-6
v=ir
5×10^-6×600
30000×10^-6
3×10^-11
v=ir
5×10^-6×600
30000×10^-6
3×10^-11
sanjay1235:
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