If current in a wire of constant resistance made 3 times, then what will be power loss?
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Explanation:
According to Ohm's law, V = IR. That is, I = V/R.
Now, if the resistance is halved and the voltage remains the same, the new value of current becomes, I
′
=
2
R
V
=
R
2V
.Thatis,I
′
=2(
R
V
)=2I.
Hence, the current will become double.
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