Question

If current in an electric bulb is decreased by 25%,
then how will power in the bulb change?​

Answer 1

Explanation:

see the attachment......

Answer 2

Power will change by 43.75 %

Explanation:

Let initially the current flowing in the bulb is i

So power will be given as $P=i^2R$

Now current is given by 25 %

So new current $i_{new}=i-0.25i=0.75i$

So new power will be given as $P_{new}=0.75i^2R=0.5625i^2R$

change in power $=i^2R-0.5625i^2R=0.4375i^2R$

So percentage change in power $=\frac{0.4375i^2R}{i^2R}=0.4375=43.75$ %

So power will change by 43.75 %

Learn more

An electric heater consumes 4.4 kW power when connected with a 220 V line voltage then,Solve the given example.

(i) Calculate the current passing through the heater.

(ii) Calculate resistance of a heater.

(iii) Calculate the energy consumed in 2 hours.

(Ans : (i) 20 A (2) 11.Q (3) 3.168 x 107 W )

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