Question

If current of 4 a flows in a wire of resistance 60 ohm calculate electrical energy consumed in 2 minutes

Answer 1

current I=4A
resistance R=60 ohm
time t=2mins=120sec.
energy consume is given by
E=power x time
E =I²R x t
E=(4)²x60 x 120
E=16x60x120
E=115,200Joules
E=115200/1000
E=115.2 kilo joules

Answer 2

Answer:

The electrical energy consumed in 2 minutes is 115.2 kJ.

Explanation:

Given that,

Current I= 4 A

Resistance R = 60 ohm

Time t = 2 min= 120 sec

The power is the product of the square of current and resistance.

The power is

$P = I^2\times R$

$P = 4\times4\times60$

$P=960\ watt=960\ J/s$

The energy consumed

$E=P\times t$

$E =960\times 120$

$E = 115200\ J= 115.2\ kJ$

Hence, The electrical energy consumed in 2 minutes is 115.2 kJ.