if D (3,4) ,E (2,-3) and F (1,1) are the midpoints of the sides of triangle ABC find the area of triangle ABC
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11
ar (ABC)=4ar (DEF)
now you find area of DEF =1/2 {3(-3-1)+2 (1-4)+1 (4+3)}=1/2 (-12-6+7)=-11/2
hence area of DEF is 11/2 square unit
so ar(ABC)=22 square unit
now you find area of DEF =1/2 {3(-3-1)+2 (1-4)+1 (4+3)}=1/2 (-12-6+7)=-11/2
hence area of DEF is 11/2 square unit
so ar(ABC)=22 square unit
Answered by
6
Area of ABC =8sq unit
I hope it help you.
I hope it help you.
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