An iceberg is floating partially immersed in sea water. If the density of sea water is 1.03 g/cc and that of ice is 0.92 g/cc, the fraction of the total volume of iceberg above the level of sea water is
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Let the volume of iceberg be V cc.
It's mass =density×volume
=0.92V g
Now, the volume of water that has this mass =mass÷density
=0.92V÷1.03 cc
=92V/103 cc
This is the volume of the water to be displaced by iceberg to float. Thus, only this much of the iceberg needs to be below water. Rest part will be above the water.
Thus, Volume above water =V-(92V/103)
=11V/103
Hence, the required fraction =11/103 [Answer]
Please note here that we have considered only mass, but actually the weight has to balanced to float. As weight is proportional to mass of the object and we only needed the fraction/ratio, mass was sufficient for that purpose.
Hope this helps. For any clarification please comment. If you like my answer and want more from me, please follow.
It's mass =density×volume
=0.92V g
Now, the volume of water that has this mass =mass÷density
=0.92V÷1.03 cc
=92V/103 cc
This is the volume of the water to be displaced by iceberg to float. Thus, only this much of the iceberg needs to be below water. Rest part will be above the water.
Thus, Volume above water =V-(92V/103)
=11V/103
Hence, the required fraction =11/103 [Answer]
Please note here that we have considered only mass, but actually the weight has to balanced to float. As weight is proportional to mass of the object and we only needed the fraction/ratio, mass was sufficient for that purpose.
Hope this helps. For any clarification please comment. If you like my answer and want more from me, please follow.
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