Question

if d>0,then write the roots of a quadratic equation ax2+bx+c=0

Answer 1

Roots are:
x= -b+√b2-4ac/2a or
x= -b-√b2-4ac/2a.

Answer 2

The given quadratic equation is: $ax^{2}+bx+c=0$

also given $d > 0$ which means the roots are real.

the roots of the quadratic equation $ax^{2}+bx+c=0$ are:

$x=\frac{-b\pm\sqrt{b^{2}-4ac } }{2a}$

That is:

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2a}, x=\frac{-b-\sqrt{b^{2}-4ac } }{2a}$