if D is a midpoint of BC, find the value of cot y / cot x.
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Answered by
7
Answer:
In △ACD
cotx
∘
=
CD
AC
.........(i)
In △ACB
cotY
∘
=
CB
AC
.........(ii)
Now D is the midpoint of BC
⇒BC=2CD
Dividing (ii) by(i)
⇒
cotx
∘
coty
∘
=
CB
AC
CD
AC
=
CD
CB
=
2CB
CB
=
2
1
Answered by
7
Given : D is the mid point of BC
To Find : value of cot y°/ cot x°
Solution:
Cot α = Base / Perpendicular
Cotx = AC/CD
Coty = AC/BC
BC = 2CD as D is the mid point of BC
=> Coty = AC/2CD
=> Coty = Cotx/2
=> Coty/ Cotx =1/ 2
Hence value of cot y°/ cot x° y is 1/2
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