Math, asked by gitasadvocate, 1 year ago

If D is a point on the side AB of ∆ABC such that AD : DB = 3:2 Find the ratio of areas of ∆ADC and ∆ABC.

Answers

Answered by anchal2099
1

Step-by-step explanation:

Answer:

given-: AD:DB=3:2

∆ADC=?

∆ABC=?

let AD=3x

let DB=2x

AD+DB=180

3x+2x=180

5x=180

x=180/5

x=36

3x=36×3=108

2x=36×2=72

Hope you like it.Please mark me as a brainlist.

Similar questions