If D is a point on the side AB of ∆ABC such that AD : DB = 3:2 Find the ratio of areas of ∆ADC and ∆ABC.
Answers
Answered by
1
Step-by-step explanation:
Answer:
given-: AD:DB=3:2
∆ADC=?
∆ABC=?
let AD=3x
let DB=2x
AD+DB=180
3x+2x=180
5x=180
x=180/5
x=36
3x=36×3=108
2x=36×2=72
Hope you like it.Please mark me as a brainlist.
Similar questions