if d is HCF of 40 and 65, find the value of integers x and y which satisfy d=40x +65y
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e40= 2*2*2*5
65=5*13
The HCF is 5
d= 5
if d= 40x+65y
then 1= 8x+13y
As there are two unknown values, the method of assumption has to be used.
Assume x=0 then y=1/13
Assume y=0 then x=1/8
If you assume x>1 or y>1 the other value will be a negative.
The two solution sets are
x=0 and y=1/13
x=1/8 and y=0
Hope This Helps :)
65=5*13
The HCF is 5
d= 5
if d= 40x+65y
then 1= 8x+13y
As there are two unknown values, the method of assumption has to be used.
Assume x=0 then y=1/13
Assume y=0 then x=1/8
If you assume x>1 or y>1 the other value will be a negative.
The two solution sets are
x=0 and y=1/13
x=1/8 and y=0
Hope This Helps :)
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