If d is HCF of 45 and 27, find x,y satisfying d=27x + 45y.
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Answered by
4
Step-by-step explanation:
HCF of 45 and 27 can be calculated as follows.
45 = 27 x 1 + 18
27 = 18 x 1 + 9
18 = 9 x 2 + 0
So, HCF (45, 27) = 9
d = 9 = 27x + 45y
From above steps, we have:
9 = 27 - 18 x 1
= 27 - (45 - 27 x 1) x 1
= 27 x 2 + 45 (-1)
Comparing this with given relation, we get,
x = 2 and y = -1
ur answer.......
Answered by
0
Answer:
x = 2 and y = -1
Step-by-step explanation:
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