If d is the HCF of 231 and 396 and d= 231x +396y then find the value of x and y
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Euclid's algorithm:Step 1. Divide the larger number by the smaller one:
396 ÷ 231 = 1 + 165;Step 2. Divide the smaller number by the above operation's remainder:
231 ÷ 165 = 1 + 66;Step 3. Divide the remainder from the step 1 by the remainder from the step 2:
165 ÷ 66 = 2 + 33;Step 4. Divide the remainder from the step 2 by the remainder from the step 3:
66 ÷ 33 = 2 + 0;At this step, the remainder is zero, so we stop:
33 is the number we were looking for, the last remainder that is not zero.
This is the greatest common factor (divisor).
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396 ÷ 231 = 1 + 165;Step 2. Divide the smaller number by the above operation's remainder:
231 ÷ 165 = 1 + 66;Step 3. Divide the remainder from the step 1 by the remainder from the step 2:
165 ÷ 66 = 2 + 33;Step 4. Divide the remainder from the step 2 by the remainder from the step 3:
66 ÷ 33 = 2 + 0;At this step, the remainder is zero, so we stop:
33 is the number we were looking for, the last remainder that is not zero.
This is the greatest common factor (divisor).
hope it helps you
please mark it brainliest answer
nandani86:
hiii
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