Question

If d is the HCF of 45 and 27 ,find d=27x + 45y.​

Answer 1

Here is your answer.....

Answer 2

ANSWER:----------

{HCF of 45 and 27}

{highest common factor )

45 = 27 x 1 + 1827

= 18 x 1 + 918

= 9 x 2 + 0

 So, {HCF (45, 27) = 9 d}

= 9 = 27x + 45y 

{ We have:9 }

= 27 - 18 x 1

   = 27 - (45 - 27 x 1) x 1  

= 27 x 2 + 45 (-1)

we get,x = 2 and y = -1

HENCE ,PROVED:-------

HOPE IT HELPS:-------

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