Question

If d is the Highest Common Factor of 32 and 60, find x and y satisfying d=32x+60y

Answer 1

HCF of 32 and 60 will be 4.

now we have to guess the value for x and y. to satisfy given equation.

d=32x+60y

4=32(2)+60(-1)

4=64-60

4=4

Hence proved

Answer 2

Answer:

The value of x=2 and y=-1.

Step-by-step explanation:

Given : If d is the Highest Common Factor of 32 and 60.

To find : The value of x and y satisfying $d=32x+60y$?

Solution :

Factor of 32 and 60

$32=2\times 2\times 2\times 2\times 2$

$32=2\times 2\times 3\times 5$

The HCF of 32 and 60 is $2\times 2=4$

So, d=4

Substitute value of d,

$4=32x+60y$

Now, we have to put the value of x and y such that the result is 4.

By hit n trial if we put x=2 and y=-1

$4=32(2)+60(-1)$

$4=64-60$

$4=4$

Equation satisfied.

Therefore, The value of x=2 and y=-1.