Math, asked by partharora167, 1 year ago

If D is the mid .point of side of side BC of a ΔABC, P and Q are two points lying respectively on the sides AB and BC such that DP is parallel to QA. Prove that ar(ΔCQP) = 1/2 ar(ΔABC).

Answers

Answered by shruti9364

3

send me the diagram

partharora167: not having

shruti9364: ok let me check

partharora167: is there some mistake in question i seemed it like that

shruti9364: i too think that only

tanishavyas06: I guess it should be 1/4 area of triangle ABC

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