if D is the midpoint of the hypotenuse AC of a right angled triangle ABC prove that BD is equal to half AC
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D is the midpoint of the hypotenuse AC of a RAT ABC. Prove that BD is equal to AC/2.
ABC is RAT with right angle at B. Angle in a semicircle is 90 degrees. So DB will be the radius = AD = DC. Hence BD = AC/2
ABC is RAT with right angle at B. Angle in a semicircle is 90 degrees. So DB will be the radius = AD = DC. Hence BD = AC/2
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