If DE || OB and EF || BC , then prove that DF || OC
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Answered by
44
hello............
if DE║OB then by B.P.T theorem
AE/EB=AD/DO .................1
EF║BC then by B.P.T theorem
AE/EB=AF/FC ..................2
BY EQ. 1 AND 2
AF/FC=AD/DO
THEN BY CONVERSE OF B.P.T THEOREM
DF║OC
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HOPE THIS WOULD HELP YOU
if DE║OB then by B.P.T theorem
AE/EB=AD/DO .................1
EF║BC then by B.P.T theorem
AE/EB=AF/FC ..................2
BY EQ. 1 AND 2
AF/FC=AD/DO
THEN BY CONVERSE OF B.P.T THEOREM
DF║OC
============================================================================================================================================
HOPE THIS WOULD HELP YOU
001rohit:
plz mark as brainlist
Answered by
11
Answer:
Step-by-step explanation:
DE║OB then by B.P.T theorem
AE/EB=AD/DO .................1
EF║BC then by B.P.T theorem
AE/EB=AF/FC ..................2
BY EQ. 1 AND 2
AF/FC=AD/DO
THEN BY CONVERSE OF B.P.T THEOREM
DF║OC
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