Question

If density gold is 19,320 kg/m3 find the relative density of gold

Answer 1

Answer:

19.320

Explanation:

Relative density = Density of substance / Density of water

= (19320 kg/m³) / (1000 kg/m³)

= 19.320

Answer 2

$\maltese \: \red{\mid{\underline{\overline{\textbf{Answer}}}\mid}}$

Density of a substance is defined as the ratio of its mass and volume.Reoresented by :-

$\maltese \: d = \frac{m}{v}$

In this equation :-

• d = density
• m = mass of substance
• v = volume of substance

Relative density of a substance is the ratio of its density to density of water. Represented by :-

$\maltese \: rd = d_s \div d_w$

In this case :

• Density of gold = 19,320kg/m^3
• Density of water = 1000kg/m^3

Now relative density of gold will be :

$\maltese \: rd = \frac{19320}{1000}$

$= 19.32 \frac{kg}{ {m}^{3} }$

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BY SCIVIBHANSHU

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