Question

If density of earth is p, radius is R
then its
gravitational field at distance
from centre will be​

Answer 1

Answer:

If the distance from the center is a, the the answer is-

Gp*(3.14)*R^3*4/(3a^2)

Explanation:

The formula for the gravitational field is-

(G*Mass of Earth)/(Distance^2)

Here the mass is not given rather the volume is.

M = density*volume

M = p*(3.14)*R^3*4/3

{The volume is (3.14)*R^3*4/3 as we are considering the earth to be a perfect sphere.}

Substituting the above value in the gravitational field equation-

Gp*(3.14)*R^3*4/(3a^2)

Note-

To signify the exponential power I have the ^ sign.

R^3 means R times three.

Hope this helps.

Answer 2

Answer:

Let us take row =¶

(πG¶R)/3

Explanation:

For the gravitaional field

we know that,

E=4/3πR¶G

Now for R=R/2

The ultimate gravitational field is

E=4/3πR/4¶G

So, E=(πR¶G)/3