Question

If density of ice is 0.9g/cm³. What part of ice remains inside and outside the sea water? (density of sea water is 1.02).​

Answer 1

Explanation:

Given:

Density of ice =0.9 g /cm^3

Density of sea water =1.02 g/ cm ^3

Consider x be the part of ice remains inside and y be the part of ice outside the sea water.

As per the law of floatation,x/y = density of ice/ density of sea water

= x/y = 0.9/1.02=0.9/1.1

×-ly and ÷ by 10

x/y=9/11

x=9/11y

Ice floats on the surface of sea water with 9/11 th of its portion over the sea surface.