Question

If deviation is minimum for an angle of incidence 40° calculate the value of angle of minimum deviation refractive index of material of the prism....

Answer 1

Answer:

Minimum deviation δ=2i−A

where A is prism angle A=60

o

So δ=40

o

we know

δ=2i−A

40=2i−60

i=50

o

For minimum angle the angle of refraction should be half of prism angle.

So r=A/2=30

o

now using the snell's law

n

air

sini=n

glass

sinr

sin50=n

glass

sin30

n

glass

=1.53 ,