The 16th term of ap 15,25/2,15/2,5 is
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4
Answer:
t(16)= -225/10
Step-by-step explanation:
t(n)=a+(n-1)d
where,a is the first term
d is the common difference
d=25/2-15
= -2.5
a=15
t(16)=15+(16-1)(-2.5)
=15+(15)(-2.5)
=15-37.5
= -22.5
= (-225/10)÷5
= -45/2
Hope it helps you.
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