If diagonal of a square 7 CM then what will be the area of a square
Attachments:
Anonymous:
hey
Answers
Answered by
1
Hello users.....
Solution:-
We know that;
Diagonal of square = a√2 unit
And
Area of square = a² sq.unit
Where, a is the side of square.
Now,
According to given :
Diagonal = 7√2
=> a√2 = 7√2 cm
=> a = 7 cm
Now,
Area of square = a²
= 7² cm²
= 49 cm² Answer
✡ Hope it helps :)
Solution:-
We know that;
Diagonal of square = a√2 unit
And
Area of square = a² sq.unit
Where, a is the side of square.
Now,
According to given :
Diagonal = 7√2
=> a√2 = 7√2 cm
=> a = 7 cm
Now,
Area of square = a²
= 7² cm²
= 49 cm² Answer
✡ Hope it helps :)
Answered by
0
Given its a square. So, let the side of the square be x.
Now.. Diagonal is given of length 7cm.
So.. In triangle BCD, BD is the diagonal of the square and BC & CD the sides. Therefore, we find the length of side of the square by Pythagoras' theorem.
Now area of square is (side)×(side)
=> x × x
=> 49/2 square cm or 24.5 square cm
Now.. Diagonal is given of length 7cm.
So.. In triangle BCD, BD is the diagonal of the square and BC & CD the sides. Therefore, we find the length of side of the square by Pythagoras' theorem.
Now area of square is (side)×(side)
=> x × x
=> 49/2 square cm or 24.5 square cm
Attachments:
Similar questions
Hindi,
7 months ago
Biology,
7 months ago
Computer Science,
7 months ago
History,
1 year ago
Science,
1 year ago