If diagonals AC & BD of a trapezium ABCD with AB parallel to DC intersect each other at O, then
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Step-by-step explanation:
ABCD is a trapezium with AB∥CD and diagonals AB and CD intersecting at O.
⇒ In △OAB and △OCD
⇒ ∠AOB=∠DOC [ Vertically opposite angles ]
⇒ ∠ABO=∠CDO [ Alternate angles ]
⇒ ∠BAO=∠OCD [ Alternate angles ]
∴ △OAB∼△OCD [ AAA similarity ]
We know that if triangles are similar, their corresponding sides are in proportion.
⇒
OC
OA
=
OD
OB
[henceproved]
I hope it will help you
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