Question

if diagonals of a cycle quadrilateral are the diameter of the circle through the verticies of the quadrilateral prove that it is a rectangle​

Answer 1

Answer:

Step-by-step explanation:

Let ABCD be a cyclic quadrilateral having diagonals BD and AC, intersecting each other at point O.

(Consider BD as a chord)

∠BCD + ∠BAD = 180° (Cyclic quadrilateral)

∠BCD = 180° − 90° = 90°

(Considering AC as a chord)

∠ADC + ∠ABC = 180° (Cyclic quadrilateral)

90° + ∠ABC = 180°

∠ABC = 90°

Each interior angle of a cyclic quadrilateral is of 90°. Hence, it is a rectangle.

Answer 2

Step-by-step explanation:

hope this will help you