if diagonals of a square field is 16 m ., then its area. is
Bunti360:
answer is 16*16/2 = 16*8 = 128
Answers
Answered by
7
use the formula of rhombus........ as square is a rhombus.....
area of a rhombus = 1/2×d1×d2
=1/2×16×16
=128m^2
area of a rhombus = 1/2×d1×d2
=1/2×16×16
=128m^2
Answered by
6
Let the sides of square is x.
Diagonal = 16.
We know that one part of square form a right angle triangle with diagonal as hypotenuse and hence it is a square its altitude and base is equal i.e. x.
Hypo^2 = altitude^2 + base^2
16^2 = x^2 + x^2
256 = 2x^2
256/2 = x^2
128 = x^2
x = √128 or 8√2.
Area of square = side^2
=(√128)^2
= 128
If you satisfied mark it brainliest.
Diagonal = 16.
We know that one part of square form a right angle triangle with diagonal as hypotenuse and hence it is a square its altitude and base is equal i.e. x.
Hypo^2 = altitude^2 + base^2
16^2 = x^2 + x^2
256 = 2x^2
256/2 = x^2
128 = x^2
x = √128 or 8√2.
Area of square = side^2
=(√128)^2
= 128
If you satisfied mark it brainliest.
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