Question

if diameter of pipe is 0.5 m and velocity of water through the pipe is 2 m/s, then discharge is
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Answer 1

Answer:

0.3925m/sec

Step-by-step explanation:

Use formula rate of flow

q = area of pipe * velocity of fluids

$q \: = \pi {r}^{2} \times velocity \\ q = 3.14 \times ({ \frac{0.5}{2} })^{2} \times 2 \\ q = 0.3925 \: {m}^{2} \: per \: sec.$

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Answer 2

Given:

The diameter of pipe = 0.5 m.

The velocity of water through the pipe = 2 m/sec.

To Find:

The discharge of the water.

Solution:

According to the formula,

The discharge of water = The area of the pipe * The velocity of water through the pipe.

Q = A*v.

Here, The area of the pipe = π r^2.

The area of the pipe = 22/7 * (0.5/2)^2.

So,

Q = 22/7 * (0.5/2)^2m^2 * 2m/sec.

Q = 0.3926 m^3/sec.

Hence, The discharge of the water is 0.3926 m^3/sec.