Question

if diameter of road roller is 0.9 m its length is 1.4 m how much area of field will presed in 500 rotation

Answer 1

radius=0.9÷2=0.45m
area covered=500×3.96

Answer 2

roller[cylinder]=
          radius,r=0.9/2m
           height,h=1.4m
the area covered in 1 rotation=$2 \pi rh$ 
                                                   =$2* \frac{22}{7}* \frac{0.9}{2} *|1.4$
                                                   =3.96m                                                 
the area covered in 500 rotation=3.96*500
                                                   =1980m