Question

If
diameter
sphere is decreased by
wie
decrease?
25% then what percent does its surface​

Answer 1

Gud Afternoon

How r u??❤️

┏_________∞◆∞_________┓

✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭

┗_________∞◆∞_________┛

Surface area = 4πR²

A = 4πR²

$\frac{\Delta A}{A}=2 \frac{\Delta R}{R}$

Here

ΔA/A => Percentage change in area

ΔR/R => Percentage change in radius or diameter

Given that,

ΔR/R = 25% = 25/100 = 1/4

Putting this value in the equation we get,

ΔA/A = 2ΔR/R

ΔA/A = 2 * 1/4 = 1/2

ΔA/A = 1/2 * 100 = 50%

When diameter or radius is decreased by 25% the area of the sphere decreases by 50%

┏_________∞◆∞_________┓

✭Hòpè Ìt Hèĺp§✭

Fòĺĺòw @zahaansajid

Pls mark as brainliest

✭Follow me and I'll follow you back ✭

┗_________∞◆∞_________┛