Math, asked by 12347011, 11 months ago

under root 6 divided by under root 2 plus under root 3​

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Answered by Samrridhi
31

The sum will be solved by rationalizing .

Step 1: Multiply root 2- root 3 with the numerator and denominator .

Step 2 : The product will be root 6 into 2 minus root 3 into 2 upon root 2 + root 3 into root 2 - root 3.

Step 3: Use the third identity that is (a+b)(a-b) = a square - b square .

Step 4 : And the answer will be root 12 - root 18 upon - 1

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Answered by AwesomeGamer
8

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