If difference between external and internal surface area of a cylindrical pipe is 44cmsq.If the metal used to prepare this pipe 99cmcube then find external and internal radius of that pipe.
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HELLO DEAR,
r= inner radius
R= outer radius
h= height of the metallic pipe = 14 cm
Difference between the Curved surface area of the outer cylinder and Curved surface area of the inner cylinder = 2πRh - 2πrh.
Given:
difference between the outside and inside curved surface area of cylinder= 44 cm2 .
so,
2πh( R - r) = 44
2 x 22/ 7 x 14 ( R - r) = 44
R - r = 1 / 2
= 0.5
Given:
the pipe is made up of metal= 99 cm³
Volume of cylindrical metallic pipe = πR²h - πr²h.
so,
22/7 x 14 (R² - r²) = 99
44(R² - r²) = 99
(R² - r²) = 9 / 4
R²-r²= 2.25
( R - r)(R + r) = 2.25
(0.5)(R + r) = 2.25
R + r = 2.25 / 0.5
R + r = 4.5
Adding up both the values we get
2R = 4.5 + 0.5 = 5
R = 2.5 cm and r = 2 cm
I HOPE ITS HELP YOU DEAR,
THANKS
r= inner radius
R= outer radius
h= height of the metallic pipe = 14 cm
Difference between the Curved surface area of the outer cylinder and Curved surface area of the inner cylinder = 2πRh - 2πrh.
Given:
difference between the outside and inside curved surface area of cylinder= 44 cm2 .
so,
2πh( R - r) = 44
2 x 22/ 7 x 14 ( R - r) = 44
R - r = 1 / 2
= 0.5
Given:
the pipe is made up of metal= 99 cm³
Volume of cylindrical metallic pipe = πR²h - πr²h.
so,
22/7 x 14 (R² - r²) = 99
44(R² - r²) = 99
(R² - r²) = 9 / 4
R²-r²= 2.25
( R - r)(R + r) = 2.25
(0.5)(R + r) = 2.25
R + r = 2.25 / 0.5
R + r = 4.5
Adding up both the values we get
2R = 4.5 + 0.5 = 5
R = 2.5 cm and r = 2 cm
I HOPE ITS HELP YOU DEAR,
THANKS
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