Math, asked by tishyasabita, 4 months ago

if difference between simple interest on a certain sum at 4% of all 6 year at 5% of 4 years is rupees 28 find the sum​

Answers

Answered by lakshmir26122006
2

Answer:

Answer

For ,

N=4years

R=4 %

We have S.I.=

100

PNR

=

100

P×4×4

=

100

16P

=0.16P

And on interest being compounded for 3 years and R=5 %, Amount=P(1+

100

R

)

N

=P(1+

100

5

)

3

=P×(1.05

3

)=1.157625P

So, C.I.=A−P=1.157625P−P=0.157625P

Given, S.I.−C.I=Rs228

=>0.16P−0.157625P=Rs228

=>0.002375P=Rs228

=>P=Rs96,000

Answered by sandhyasubhash91
13

Answer:

Let principal =P

First case,

R =4% T =6years

Intt(1) = P×4×6/100 = 24P/100

Second case,

R =5%

T = 4 years

Intt(2) = P×5×4/100 = 20P/100

Difference = Intt(1) - Intt (2)

= 24P/100 - 20P/100

= 4P/100

It is given that the difference is 28

Therefore 4P/100 = 28

P = 28 × 100/4 = 700

Ans = Rs. 700

Step-by-step explanation:

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