Question

If digit is chosen at random from the digit 1, 2, 3, 4, 5, 6, 7, 8, 9, then the probability that it is odd, is
(a)$\frac{4}{9}$
(b)$\frac{5}{9}$
(c)$\frac{1}{9}$
(d)$\frac{2}{3}$

Answer 1

SOLUTION :  

The correct option is (b) : 5/9 .

Given : Digits are chosen from 1, 2, 3, 4, 5, 6, 7, 8, 9  

Total number of outcomes = 9

Let E = Event of getting a odd digit

Odd digits are = 1, 3, 5, 7, 9

Number of outcome favourable to E = 5

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 5/9

Hence, the probability of getting odd digit , P(E) = 5/9

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Answer 2

odd no. = 1, 3, 5, 7, 9 (5)

total outcomes = 9

probability = 5/9

b)5/9 is correct

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