Question

If displacement of a body s = (200+_ 5 )meter and time taken by it is t= (20+_0.2)seconds then find the percentage error in the calculation of acceleration?

Answer 1

Answer:

In this question

s = 200

t = 20

Δs = 5

Δt = 0.2

We know that displacement = velocity × time

∴ s = v × t

For error in velocity we know that

Δv/v = Δs/s + Δt/t

or, Δv/v = 5/200 + 0.2/20

or, Δv/v = 0.025 + 0.01

= 0.035

∴ Percentage error in velocity = 0.035 × 100 = 3.5%