Physics, asked by noorwalia1903, 10 months ago

if displacement wave equation of a sound wave is given as s=Asin(Bx-Ct) then dimensions of A^2*C/B is ( s is displacement of particle which is at x=x at any time t)​

Answers

Answered by abhi178
23

Given : if the displacement wave equation of a sound wave is given as s = Asin(Bx - Ct)

To find : The dimensions of A²C/B

solution : dimension of A = dimension of s

= [L]

we know, sine function is a dimensionless quantity.

⇒(Bx - Ct) is a dimensionless quantity.

⇒Bx and Ct are also dimensionless quantities.

so dimension of B × dimension of x = 1

⇒dimension of B = 1/dimension of x = 1/[L]

⇒dimension of B = [L¯¹]

again, dimension of C × dimension of t = 1

⇒dimension of C = 1/dimension of t = 1/[T]

⇒dimension of C = [T¯¹]

dimension of A²C/B = [L]² × [T¯¹]/[L¯¹]

= [L³T¯¹]

Therefore the dimensions of A²C/B = [L³T¯¹]

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