Math, asked by pinkupearlsom, 9 months ago

Solve 3x-4y-1=0,2x-8/3y+5=0 using substitution

Answers

Answered by manidipta2006
1

Answer:

x=4, y=11/4

Step-by-step explanation:

3x-4y-1=0

=>3x-4y=1

=>3x=1+4y

=>x=1+4y/3------(i)

2x-8/3y+5=0

=>2x-8=0

=>2x=8

=>x=4----(ii)

Substituting the value of (ii) in (i), we get:

x=1+4y/3

=>4=1+4y/3

=>1+4y=12

=>4y=12-1=11

=>y=11/4

Hence, x=4 and y=11/4

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