Solve 3x-4y-1=0,2x-8/3y+5=0 using substitution
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Answer:
x=4, y=11/4
Step-by-step explanation:
3x-4y-1=0
=>3x-4y=1
=>3x=1+4y
=>x=1+4y/3------(i)
2x-8/3y+5=0
=>2x-8=0
=>2x=8
=>x=4----(ii)
Substituting the value of (ii) in (i), we get:
x=1+4y/3
=>4=1+4y/3
=>1+4y=12
=>4y=12-1=11
=>y=11/4
Hence, x=4 and y=11/4
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