Question

if displacement x of a particle moving in straight line is given by
$x = {t}^{3} - 12t$
where t is time in sec and x in metre . find the acceleration of the particle, when velocity of the particle is 0

Answer 1

Hey friend,
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Question : If displacement x of a particle moving in straight line is given by x= t^3 - 12t

where t is time in sec and x in metre . find the acceleration of the particle, when velocity of the particle is 0

Solution:

The above question is solved by differentiation.

The differentiation of displacement wrt time gives velocity.

The differentiation of  velocity wrt time  gives acceleration.

Hence in the question x stands displacement.

we will differentiate the above expression.

on differentiating the expression becomes

v =3t^2 -12

Once again we will differentiate the expression to get expression for acceleration .

a= 6t 

Now we will find when v =0 what is t 

hence in expression v= 3t^2 -12 put v =0

Which gives t=2 sec put this in expression of acceleration.

a= 6t    t=2     hence a = 12m/sec^2   

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