Chemistry, asked by Neerajakani9743, 11 months ago

If dissociation constant of Ammonia is 1.8×10^-5. What is the dissociation constant of its conjugate acid, Ammonia:[Kw = 10^-14]

Answers

Answered by arunsomu13

2

Answer:

Explanation:

Ka x Kb =Kw

therefore Ka= Kw/Kb=10^-14/(1.8)(10^-5)

=0.55 x 10^-9

=5.5 x 10^-10

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