Question

If dissociation constant of Ammonia is 1.8×10^-5. What is the dissociation constant of its conjugate acid, Ammonia:[Kw = 10^-14]

Answer 1

Answer:

Explanation:

Ka x Kb =Kw

therefore Ka= Kw/Kb=10^-14/(1.8)(10^-5)

                    =0.55 x 10^-9

                    =5.5 x 10^-10