Question

If distance between the points P(3,y) and Q(9,-2) is 10 units, find the value of 'y'.

Explain step by step.
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Answer 1

Answer:

Step-by-step explanation:

The eqution to calculate the distance between two points (x1,y1),(x2,y2)

[(x1-x2)^2+（y1-y2)^2]^1/2=the distance

So,for this question,

[(3–9)^2+(y+2)^2]^1/2=10

6^2+(y+2)^2=100

y=10 or -6.                                                                        

Answer 2

Answer:

6

Step-by-step explanation:

Using Pythagorean Theorem:

d =

$\sqrt{( {x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

X2 = 9

X1 = 3

y2 = -2

y1 = y

d = 10

Substituting and squaring on both sides,

100 = (9-3) ^2 + ( -2 - y ) ^2

100 = 36 + ( -1 ( 2+y ) ) ^ 2

64 = (2 + y ) ^2

Taking square root on both sides

8 = 2 + y

So

y = 6