If ∫dx(x+2)(x2+1)=alog∣1+x2∣+btan−1x+15log∣x+2∣+C,then(A)a=−110,b=−25(B)a=110,b=−25(C)a=−110,b=25(D)a=110,b=25
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If x3dx√1−x2=a(1−x2)32+b√1−x2+C,then
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