If E and F are the midpoint of equal sides AB and AC of a triangle ABC then
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Given E and F are mid point of equal sides AB and AC of triangle ABC
In ΔABF and ΔACE
AB=AC (given )
∠A=∠A (common angle )
AF=AE (halves of equal sides)
∴ ΔABF≅ΔACE (SAS rule)
∴ BF=CF (CPCT)
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Answer:
Given E and F are mid point of equal sides AB and AC of triangle ABC
In ΔABF and ΔACE
AB=AC (given )
∠A=∠A (common angle )
AF=AE (halves of equal sides)
∴ ΔABF≅ΔACE (SAS rule)
∴ BF=CF (CPCT)
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